Oxidation state of nitrogen is correctly given for Compound Oxidation state (a) NH = NH -1 (b) N2O3 -3 (c) NH2-NH2 +2 (d) N2O4 -5

Question

Oxidation state of nitrogen is correctly given for Compound Oxidation state (a) NH = NH -1 (b) N2O3 -3 (c) NH2-NH2 +2 (d) N2O4 -5 (A) a (B) b (C) c (D) d

Tardigrade Admin · Accepted Answer

N2O3 ⇒ 2x-6=0 ⇒ x=+3 N2H4 ⇒ 2x+4=0 ⇒ x=-2 N2O4 ⇒ 2x-8=0 ⇒ x=+4

Q. Oxidation state of nitrogen is correctly given for

Compound Oxidation state

(a) $N H = N H$ $- 1$

(b) $N_{2} O_{3}$ $- 3$

(c) $N H_{2} - N H_{2}$ +2

(d) $N_{2} O_{4}$ -5

a

b

c

d

$N_{2} O_{3} \Rightarrow 2 x - 6 = 0$
$\Rightarrow x = + 3$
$N_{2} H_{4} \Rightarrow 2 x + 4 = 0$
$\Rightarrow x = - 2$
$N_{2} O_{4} \Rightarrow 2 x - 8 = 0$
$\Rightarrow x = + 4$

	Compound	Oxidation state
(a)	$N H = N H$	$- 1$
(b)	$N_{2} O_{3}$	$- 3$
(c)	$N H_{2} - N H_{2}$	+2
(d)	$N_{2} O_{4}$	-5

Q. Oxidation state of nitrogen is correctly given for Compound Oxidation state (a) NH=NH −1 (b) N2​O3​ −3 (c) NH2​−NH2​ +2 (d) N2​O4​ -5

a

b

c

d

N2​O3​⇒2x−6=0 ⇒x=+3 N2​H4​⇒2x+4=0 ⇒x=−2 N2​O4​⇒2x−8=0 ⇒x=+4

Q. Oxidation state of nitrogen is correctly given for

Compound Oxidation state

(a) $N H = N H$ $- 1$

(b) $N_{2} O_{3}$ $- 3$

(c) $N H_{2} - N H_{2}$ +2

(d) $N_{2} O_{4}$ -5

$N_{2} O_{3} \Rightarrow 2 x - 6 = 0$
$\Rightarrow x = + 3$
$N_{2} H_{4} \Rightarrow 2 x + 4 = 0$
$\Rightarrow x = - 2$
$N_{2} O_{4} \Rightarrow 2 x - 8 = 0$
$\Rightarrow x = + 4$