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Tardigrade
Question
Chemistry
Oxidation state of middle carbon in carbon suboxide is
Q. Oxidation state of middle carbon in carbon suboxide is
1999
217
Redox Reactions
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A
0
58%
B
1
14%
C
2
20%
D
- 4
8%
Solution:
Structure of
C
3
O
2
:
O
−
2
=
C
+
2
=
C
0
=
C
+
2
=
O
−
2
Oxidation state of middle carbon is zero.