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Tardigrade
Question
Chemistry
Oxidation state of cobalt in Na [ Co ( CO )4] is
Q. Oxidation state of cobalt in
N
a
[
C
o
(
CO
)
4
]
is
3748
239
Coordination Compounds
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A
+1
17%
B
0
33%
C
-2
0%
D
-1
50%
Solution:
N
a
[
C
o
(
CO
)
4
]
:
1
+
x
+
4
×
0
,
⇒
x
=
−
1