Oxidation of succinate ion produces ethylene and carbon dioxide gases. On passing 0.2 Faraday electricity through an aqueous solution of potassium succinate, the total volume of gases (at both cathode and anode) at STP (1 atm and 273 K) is :

Question

Oxidation of succinate ion produces ethylene and carbon dioxide gases. On passing 0.2 Faraday electricity through an aqueous solution of potassium succinate, the total volume of gases (at both cathode and anode) at STP (1 atm and 273 K) is : (A) 2.24 L (B) 4.48 L (C) 6.72 L (D) 8.96 L

Tardigrade Admin · Accepted Answer

Total equivalents of C2H4+CO2+H2 = 0.2+0.2+0.2 = 0.6 Total moles of gases = (0.2/2)+(0.2/1)+(0.2/2) = 0.4 v = (nRT/P) = (0.4×0.0821×273/1) = 8.96 L

Q. Oxidation of succinate ion produces ethylene and carbon dioxide gases. On passing $0.2$ Faraday electricity through an aqueous solution of potassium succinate, the total volume of gases (at both cathode and anode) at STP ( $1 a t m$ and $273 K$ ) is :

$2.24 L$

$4.48 L$

$6.72 L$

$8.96 L$

Total equivalents of $C_{2} H_{4} + C O_{2} + H_{2} = 0.2 + 0.2 + 0.2 = 0.6$
Total moles of gases $= \frac{0.2}{2} + \frac{0.2}{1} + \frac{0.2}{2} = 0.4$
$v = \frac{n RT}{P} = \frac{0.4 \times 0.0821 \times 273}{1}$
$= 8.96 L$

Q. Oxidation of succinate ion produces ethylene and carbon dioxide gases. On passing 0.2 Faraday electricity through an aqueous solution of potassium succinate, the total volume of gases (at both cathode and anode) at STP (1atm and 273K) is :

2.24L

4.48L

6.72L

8.96L