Oxidation of one molecule of glucose will yield 36 ATP in proportion of

Question

Oxidation of one molecule of glucose will yield 36 ATP in proportion of (A) All text36 ATP in mitochondria (B)  text6 ATP outside the mitochondria and text30 inside mitochondria. (C)  text2 ATP in glycolysis and text34 ATP in Kreb's cycle (D)  text2 ATP outside the mitochondria and text34 inside mitochondria.

Tardigrade Admin · Accepted Answer

text2 ATP are synthesized in glycolysis through phosphorylation and the remaining text34 ATP are synthesized in mitochondria through Kreb's cycle and ETS.

Q. Oxidation of one molecule of glucose will yield 36 ATP in proportion of

All $36 ATP$ in mitochondria

$6 ATP$ outside the mitochondria and $30$ inside mitochondria.

$2 ATP$ in glycolysis and $34 ATP$ in Kreb's cycle

$2 ATP$ outside the mitochondria and $34$ inside mitochondria.

$2 ATP$ are synthesized in glycolysis through phosphorylation and the remaining $34 ATP$ are synthesized in mitochondria through Kreb's cycle and ETS.

Q. Oxidation of one molecule of glucose will yield 36 ATP in proportion of

All 36 ATP in mitochondria

6 ATP outside the mitochondria and 30 inside mitochondria.

2 ATP in glycolysis and 34 ATP in Kreb's cycle

2 ATP outside the mitochondria and 34 inside mitochondria.

2 ATP are synthesized in glycolysis through phosphorylation and the remaining 34 ATP are synthesized in mitochondria through Kreb's cycle and ETS.

All $36 ATP$ in mitochondria

$6 ATP$ outside the mitochondria and $30$ inside mitochondria.

$2 ATP$ in glycolysis and $34 ATP$ in Kreb's cycle

$2 ATP$ outside the mitochondria and $34$ inside mitochondria.

$2 ATP$ are synthesized in glycolysis through phosphorylation and the remaining $34 ATP$ are synthesized in mitochondria through Kreb's cycle and ETS.