Question

Oxidation numbers of carbon in $C{H}_{2}C{l}_2,C{O}_2$ and $C{O}_3^{2-}$ are respectively

• A. $0,+4,+4$
• B. $+2,+2,-2$
• C. $+4,+4,+4$
• D. $-4,+4,+2$

Answer 1

Answer: (A)

:
$C{H}_{2}C{l}_2$
$C{O}_2$
$C{O}_3^{2-}$
$+x+2(+1)+2(-1)=0$
$x+2(-2)=0$
$x+3(-2)=-2$
$x+2-2=0$
$x-4=0$
$x-6=-2$
$x=0x=+4$
$x=+4$