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Chemistry
Oxidation numbers of carbon in CH2Cl2,CO2 and CO32- are respectively
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Q. Oxidation numbers of carbon in $ C{{H}_{2}}C{{l}_{2}},C{{O}_{2}} $ and $ CO_{3}^{2-} $ are respectively
AMU
AMU 1998
A
$ 0,+4,+4 $
B
$ +2,+2,-2 $
C
$ +4,+4,+4 $
D
$ -4,+4,+2 $
Solution:
:
$ C{{H}_{2}}C{{l}_{2}} $
$ C{{O}_{2}} $
$ CO_{3}^{2-} $
$ +x+2(+1)+2(-1)=0 $
$ x+2(-2)=0 $
$ x+3(-2)=-2 $
$ x+2-2=0 $
$ x-4=0 $
$ x-6=-2 $
$ x=0\,x=+4 $
$ x=+4 $