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Question
Chemistry
Oxidation number of Xe in Ba 2 XeO 6 is
Q. Oxidation number of
X
e
in
B
a
2
X
e
O
6
is
1942
161
Redox Reactions
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A
+8
39%
B
+10
40%
C
+4
10%
D
+3
11%
Solution:
B
a
2
+
2
X
e
O
6
x
−
2
:
2
(
+
2
)
+
x
+
6
(
−
2
)
=
0
⇒
x
=
+
8