Oxidation number of sulphur in peroxomonosulphuric acid (H2SO5) is

Question

Oxidation number of sulphur in peroxomonosulphuric acid (H2SO5) is (A) +4 (B) +2 (C) +6 (D) -2

Tardigrade Admin · Accepted Answer

H2SO5 <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/49831e51693f7a7bbb22c4d3ccb1a90a-.jpeg" /> Oxidation number of O in peroxo linkage = -1 Oxidation number of other O atoms = -2 +2 + x - 6- 2 = 0 or x = +6

Q. Oxidation number of sulphur in peroxomonosulphuric acid $(H_{2} S O_{5})$ is

$+ 4$

$+ 2$

$+ 6$

$- 2$

$H_{2} S O_{5}$

Oxidation number of $O$ in peroxo linkage $= - 1$
Oxidation number of other $O$ atoms $= - 2$
$+ 2 + x - 6 - 2 = 0$ or $x = + 6$

Q. Oxidation number of sulphur in peroxomonosulphuric acid (H2​SO5​) is

+4

+2

+6

−2