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Question
Chemistry
Oxidation number of P in H4P2O5,H4P2O6,H4P2O7 respectively are
Q. Oxidation number of P in
H
4
P
2
O
5
,
H
4
P
2
O
6
,
H
4
P
2
O
7
respectively are
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A
+ 3, + 5, + 4
B
+ 4, + 3, + 5
C
+ 3, + 4, + 5
D
+ 5, + 3, + 4
Solution:
H
4
P
2
O
6
=
4
×
1
+
2
×
a
−
5
×
2
=
0
a
=
+
3
H
4
P
2
O
6
=
4
×
1
+
2
×
a
−
6
×
2
=
0
a
=
+
4
H
4
P
2
O
7
=
4
×
1
+
2
×
a
−
7
×
2
=
0
a
=
+
5