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Q. Oxidation number of P in $ {{H}_{4}}{{P}_{2}}{{O}_{5}},{{H}_{4}}{{P}_{2}}{{O}_{6}},{{H}_{4}}{{P}_{2}}{{O}_{7}} $ respectively are

VMMC MedicalVMMC Medical 2015

Solution:

$ {{H}_{4}}{{P}_{2}}{{O}_{6}}=4\times 1+2\times a-5\times 2=0 $ $ a=+3 $ $ {{H}_{4}}{{P}_{2}}{{O}_{6}}=4\times 1+2\times a-6\times 2=0 $ $ a=+4 $ $ {{H}_{4}}{{P}_{2}}{{O}_{7}}=4\times 1+2\times a-7\times 2=0 $ $ a=+5 $