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Tardigrade
Question
Chemistry
Oxidation number of N in NH3 is
Q. Oxidation number of N in
N
H
3
is
1430
194
Redox Reactions
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A
+
5
3%
B
+
3
11%
C
0
7%
D
−
3
79%
Solution:
N
∗
H
3
x
+
3
(
+
1
)
=
0
,
x
=
−
3.