Q. Oxidation number of $^{'} N^{'}$ in $N_{3} H$ is

1791 250 Rajasthan PETRajasthan PET 2002 Report Error

A

$- \frac{1}{3}$

B

$+ 3$

C

0

D

$- 3$

Solution:

Let the oxidation number of N is $x$ in $N_{3} H$ (hydrazoic acid) $3 x + 1 = 0$ $3 x = - 1$ $x = - \frac{1}{3}$