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Q. Oxidation number of $ 'N' $ in $ {{N}_{3}}H $ is

Rajasthan PETRajasthan PET 2002

Solution:

Let the oxidation number of N is $ x $ in $ {{N}_{3}}H $ (hydrazoic acid) $ 3x+1=0 $ $ 3x=-1 $ $ x=-\frac{1}{3} $