Oxidation number of Mn atom in KMnO4 is

Question

Oxidation number of Mn atom in KMnO4 is (A) 6 (B) 7 (C) 14 (D) 5

Tardigrade Admin · Accepted Answer

The sum of the oxidation numbers of all the atoms in a molecule of a neutral compound is zero. Let the oxidation number of Mn is ' x ' in KMnO 4 (+1)+x+4(-2)=0 x-7=0 x=7

Q. Oxidation number of $M n$ atom in $K M n O_{4}$ is

6

7

14

5

The sum of the oxidation numbers of all the atoms in a molecule of a neutral compound is zero.
Let the oxidation number of $M n$ is ' $x$ ' in $K M n O_{4}$
$(+ 1) + x + 4 (- 2) = 0$
$x - 7 = 0$
$x = 7$

Q. Oxidation number of Mn atom in KMnO4​ is

6

7

14

5

The sum of the oxidation numbers of all the atoms in a molecule of a neutral compound is zero. Let the oxidation number of Mn is ' x ' in KMnO4​ (+1)+x+4(−2)=0 x−7=0 x=7

Q. Oxidation number of $M n$ atom in $K M n O_{4}$ is

The sum of the oxidation numbers of all the atoms in a molecule of a neutral compound is zero.
Let the oxidation number of $M n$ is ' $x$ ' in $K M n O_{4}$
$(+ 1) + x + 4 (- 2) = 0$
$x - 7 = 0$
$x = 7$