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  4. Oxidation number of Mn atom in KMnO4 is

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Q. Oxidation number of $Mn$ atom in $ KMnO_{4} $ is

BHUBHU 2007

Solution:

The sum of the oxidation numbers of all the atoms in a molecule of a neutral compound is zero.
Let the oxidation number of $Mn$ is ' $x$ ' in $KMnO _{4}$
$(+1)+x+4(-2)=0 $
$x-7=0 $
$x=7$