Q. Oxidation number of carbon in $H_{2} C_{2} O_{4}$ is

1842 231 Redox Reactions Report Error

A

$+ 4$

8%

B

$+ 3$

79%

C

$+ 2$

10%

D

$- 2$

3%

Solution:

$H_{2} C_{2} * O_{4}$
$2 + 2 x - 2 \times 4 = 0; 2 x = 8 - 2 = 6$
$x = \frac{6}{2} = + 3$