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Q. Oxidation number of carbon in $H_{2}C_{2}O_{4}$ is

Redox Reactions

Solution:

$H_{2} \overset{*}{C_{2}}O_{4}$
$2 + 2x - 2 \times 4 = 0; 2x = 8 - 2 = 6$
$x=\frac{6}{2}=+3$