Question

Oxidation number of carbon in $C{H}_{2}C{l}_2$ is :

• A. 0
• B. 2
• C. 3
• D. 5

Answer 1

Answer: (A)

Oxidation number of $Cl=-1,H=+1$
In $C{H}_{2}C{l}_2$, let oxidation number of $C=x$
$x+2(1)+2(-1)=0$
$x+2-2=0$
$x=0$