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Q. Oxidation number of carbon in $ CH_2Cl_2 $ is :

AFMCAFMC 2004

Solution:

Oxidation number of $Cl =-1, H =+1$
In $CH _{2} Cl _{2}$, let oxidation number of $C =x$
$x+2(1)+2(-1)=0$
$x+2-2=0 $
$x=0$