Out of TiF 62-, CoF 63-, Cu 2 Cl 2 and NiCl 42- (At. no. Z of Ti =22, Co =27, Cu =29, Ni =28 ), the colourless species are

Question

Out of TiF 62-, CoF 63-, Cu 2 Cl 2 and NiCl 42- (At. no. Z of Ti =22, Co =27, Cu =29, Ni =28 ), the colourless species are (A) TiF2-6 and CoF3-6 (B) Cu2Cl2 and NiCl2-4 (C) Cu2Cl2 and TiF2-6 (D) CoF3-6 and NiCl2-4

Tardigrade Admin · Accepted Answer

TiF 62- Ti +4 arrow[ Ar ] 0 unpair e - ⇒ Dimagnetic/ colourless CoF 63- Co +3 arrow[ Ar ] 3 d 6 4 unpair e - ⇒ Paramagnetic/ coloured Cu 2 Cl 2 Cu + arrow[ Ar ] 3 d 10 0 unpair e - ⇒ Dimagnetic/ colourless NiCl 42- Ni +2 arrow[ Ar ] 3 d 8 2 unpair e - ⇒ Paramagnetic/ coloured

Q. Out of $T i F_{6}^{2 -}, C o F_{6}^{3 -}, C u_{2} C l_{2}$ and $N i C l_{4}^{2 -}$ (At. no. $Z$ of $T i = 22, C o = 27, C u = 29$ , $N i = 28$ ), the colourless species are

$T i F_{6}^{2 -}$ and $C o F_{6}^{3 -}$

$C u_{2} C l_{2}$ and $N i C l_{4}^{2 -}$

$C u_{2} C l_{2}$ and $T i F_{6}^{2 -}$

$C o F_{6}^{3 -}$ and $N i C l_{4}^{2 -}$

Q. Out of TiF62−​,CoF63−​,Cu2​Cl2​ and NiCl42−​ (At. no. Z of Ti=22,Co=27,Cu=29, Ni=28 ), the colourless species are

TiF62−​ and CoF63−​

Cu2​Cl2​ and NiCl42−​

Cu2​Cl2​ and TiF62−​

CoF63−​ and NiCl42−​

TiF62−​Ti+4→[Ar]0 unpair e−⇒ Dimagnetic/ colourless CoF63−​Co+3→[Ar]3d64 unpair e −⇒ Paramagnetic/ coloured Cu2​Cl2​Cu+→[Ar]3d100 unpair e−⇒ Dimagnetic/ colourless NiCl42−​Ni+2→[Ar]3d82 unpair e−⇒ Paramagnetic/ coloured

Q. Out of $T i F_{6}^{2 -}, C o F_{6}^{3 -}, C u_{2} C l_{2}$ and $N i C l_{4}^{2 -}$ (At. no. $Z$ of $T i = 22, C o = 27, C u = 29$ , $N i = 28$ ), the colourless species are

$T i F_{6}^{2 -}$ and $C o F_{6}^{3 -}$

$C u_{2} C l_{2}$ and $N i C l_{4}^{2 -}$

$C u_{2} C l_{2}$ and $T i F_{6}^{2 -}$

$C o F_{6}^{3 -}$ and $N i C l_{4}^{2 -}$