Out of the two compounds shown below, the vapour pressure of B at a particular temperature is expected to be

Question

Out of the two compounds shown below, the vapour pressure of B at a particular temperature is expected to be (A) higher than that of A (B) lower than that of B (C) same as that of A (D) can be higher or lower depending upon the size of the vessel.

Tardigrade Admin · Accepted Answer

Due to intramolecular H- bonding in o-nitrophenol it exists as a monomer while due to intermolecular H-bonding in p-nitrophenol it exists as an associate molecule. As a result, vapour pressure of a o-nitrophenol is higher than that of a p-nitrophenol.

Q. Out of the two compounds shown below, the vapour pressure of B at a particular temperature is expected to be

higher than that of A

lower than that of B

same as that of A

can be higher or lower depending upon the size of the vessel.

Due to intramolecular $H -$ bonding in $o$ -nitrophenol it exists as a monomer while due to intermolecular $H$ -bonding in $p$ -nitrophenol it exists as an associate molecule. As a result, vapour pressure of a $o$ -nitrophenol is higher than that of a $p$ -nitrophenol.

Q. Out of the two compounds shown below, the vapour pressure of B at a particular temperature is expected to be

higher than that of A

lower than that of B

same as that of A

can be higher or lower depending upon the size of the vessel.

Due to intramolecular H− bonding in o-nitrophenol it exists as a monomer while due to intermolecular H-bonding in p-nitrophenol it exists as an associate molecule. As a result, vapour pressure of a o-nitrophenol is higher than that of a p-nitrophenol.

Due to intramolecular $H -$ bonding in $o$ -nitrophenol it exists as a monomer while due to intermolecular $H$ -bonding in $p$ -nitrophenol it exists as an associate molecule. As a result, vapour pressure of a $o$ -nitrophenol is higher than that of a $p$ -nitrophenol.