Out of N , O , Ne , Na and Na +, which of these species will have the maximum and minimum ionization energy respectively:

Question

Out of N , O , Ne , Na and Na +, which of these species will have the maximum and minimum ionization energy respectively: (A) Na +, O (B) Na +, Na (C) N, Ne (D) Ne ,N

Tardigrade Admin · Accepted Answer

Na + and Ne are isoelectronic but Na + has more protons. So, its I.E. is highest. Na is alkali metal with a very low I.E.

Q. Out of $N, O, N e, N a$ and $N a^{+},$ which of these species will have the maximum and minimum ionization energy respectively:

$N a^{+}, O$

$N a^{+}, N a$

$N, N e$

$N e, N$

$N a^{+}$ and $N e$ are isoelectronic but $N a^{+}$ has more protons. So, its $I . E .$ is highest.

$N a$ is alkali metal with a very low $I . E .$

Q. Out of N,O,Ne,Na and Na+, which of these species will have the maximum and minimum ionization energy respectively:

Na+,O

Na+,Na

N,Ne

Ne,N