Out of Relative stabilities order is

Question

Out of <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/0dc9b502cd61d1ee5fe6945e527e38fc-.jpeg" /> Relative stabilities order is (A) 4 < 2 < 3 < 1 (B) 2 < 4 < 3 < 1 (C) 4 < 2 < 1 < 3 (D) 2 < 4 < 1 < 3

Tardigrade Admin · Accepted Answer

Due to the presence of phenyl group the stabilities of the carbocations 1,2 and 3 are greater than cation 4, (due to resonance). Further the presence of electron-donating groups on phenyl ring increases the stability of carbocation.

Hence, cation 1 and 3 are more stable than cation 2. Moreover - OMe group shows

+ M

effect which is more prominent than +\effect of - Me group. Thus, cation 1 is more stable than cation

3.

So, the correct order is,

4 < 2 < 3 < 1

Q. Out of

Relative stabilities order is

$4 < 2 < 3 < 1$

$2 < 4 < 3 < 1$

$4 < 2 < 1 < 3$

$2 < 4 < 1 < 3$

Q. Out of Relative stabilities order is

4<2<3<1

2<4<3<1

4<2<1<3

2<4<1<3

Q. Out of

Relative stabilities order is

$4 < 2 < 3 < 1$

$2 < 4 < 3 < 1$

$4 < 2 < 1 < 3$

$2 < 4 < 1 < 3$