Out of 10 white, 8 black and 6 red balls, the number of ways in which one or more balls can be selected is (assuming balls of the same colour are identical)

Question

Out of 10 white, 8 black and 6 red balls, the number of ways in which one or more balls can be selected is (assuming balls of the same colour are identical) (A) 681 (B) 691 (C) 679 (D) 692

Tardigrade Admin · Accepted Answer

Required number of ways =(10 + 1)(8 + 1)(6 + 1)-1 =11× 9× 7-1 =693-1 =692

Q. Out of $10$ white, $8$ black and $6$ red balls, the number of ways in which one or more balls can be selected is (assuming balls of the same colour are identical)

$681$

$691$

$679$

$692$

Required number of ways
$= (10 + 1) (8 + 1) (6 + 1) - 1$
$= 11 \times 9 \times 7 - 1$
$= 693 - 1$
$= 692$

Q. Out of 10 white, 8 black and 6 red balls, the number of ways in which one or more balls can be selected is (assuming balls of the same colour are identical)

681

691

679

692