Out of 1.0 g dioxygen 1.0 g (atomic) oxygen and 1.0 g ozone the maximum number of oxygen atoms are contained in

Question

Out of 1.0 g dioxygen 1.0 g (atomic) oxygen and 1.0 g ozone the maximum number of oxygen atoms are contained in (A) 1.0 g of atomic oxygen (B) 1.0 g of ozone (C) 1.0 g of oxygen gas (D) All contain same number of atoms

Tardigrade Admin · Accepted Answer

Since mass of oxygen is same. Therefore, the number of gm-atom and also the number of atoms will be same in all the samples
i.e., Atoms of oxygen

= \frac{1 \times 2}{32}

in

O_{2}

= \frac{1}{16}

in atomic oxygen

= \frac{1 \times 3}{48}

in

O_{3}

Q. Out of 1.0 g dioxygen 1.0 g (atomic) oxygen and 1.0 g ozone the maximum number of oxygen atoms are contained in

1.0 g of atomic oxygen

1.0 g of ozone

1.0 g of oxygen gas

All contain same number of atoms

Since mass of oxygen is same. Therefore, the number of gm-atom and also the number of atoms will be same in all the samples i.e., Atoms of oxygen =321×2​ in O2​ =161​ in atomic oxygen =481×3​ in O3​

Since mass of oxygen is same. Therefore, the number of gm-atom and also the number of atoms will be same in all the samples
i.e., Atoms of oxygen $= \frac{1 \times 2}{32}$ in $O_{2}$
$= \frac{1}{16}$ in atomic oxygen $= \frac{1 \times 3}{48}$ in $O_{3}$