One turn of the helix in a B-form DNA is approximately

Question

One turn of the helix in a B-form DNA is approximately (A) 20 nm (B) 0.34 nm (C) 3.4 nm (D) 2 nm

Tardigrade Admin · Accepted Answer

B-DNA is helical structure with 20A diameter and the distance between the two base pairs is 3.4 overseto mathopA and there are 10 base pairs in each turn or pitch (one round). Hence, one turn of the helix is approximately 34 overseto mathopA or 3.4 nm (10 overseto mathopA = 1.0 nm)

Q. One turn of the helix in a B-form DNA is approximately

20 nm

0.34 nm

3.4 nm

2 nm

B-DNA is helical structure with 20A diameter and the distance between the two base pairs is 3.4 $A o$ and there are 10 base pairs in each turn or pitch (one round). Hence, one turn of the helix is approximately 34 $A o$ or 3.4 nm (10 $A o$ = 1.0 nm)

Q. One turn of the helix in a B-form DNA is approximately

20 nm

0.34 nm

3.4 nm

2 nm

B-DNA is helical structure with 20A diameter and the distance between the two base pairs is 3.4 Ao and there are 10 base pairs in each turn or pitch (one round). Hence, one turn of the helix is approximately 34 Ao or 3.4 nm (10 Ao = 1.0 nm)

B-DNA is helical structure with 20A diameter and the distance between the two base pairs is 3.4 $A o$ and there are 10 base pairs in each turn or pitch (one round). Hence, one turn of the helix is approximately 34 $A o$ or 3.4 nm (10 $A o$ = 1.0 nm)