Q.
One mole of monatomic gas and three moles of diatomic gas are put together in a container. The molar specific heat (in JK−1mol−1 ) at constant volume is (Let R=8JK−1mol−1 )
n1=1 mole f1=3 n2=3 moles f2=5 R=8JK−1mol−1
Molar specific heat are given by the weighted means of the gases. Cvf=n1+n2n1×Cv1+n2×CV2 Cvf=41×23R+3×25R =83R+815R =818R Cvf=18