One mole of Mg3N2 react with excess of water to form x mole of Ammonia and One mole of LiH react with H2O to give y mole of H2 find ((x/2) + y)=

Question

One mole of Mg3N2 react with excess of water to form x mole of Ammonia and One mole of LiH react with H2O to give y mole of H2 find ((x/2) + y)= (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/a8be94cea8802541c3421e990d2d49c9-.png" /> LiH+H2O arrow H2+LiOH (y) (x/2)+y=(2/2)+1=1+1=2

Q. One mole of $M g_{3} N_{2}$ react with excess of water to form $x$ mole of Ammonia and One mole of $L i H$ react with $H_{2} O$ to give $y$ mole of $H_{2}$ find $(\frac{x}{2} + y) =$

$L i H + H_{2} O \to H_{2} + L i O H$
$(y)$
$\frac{x}{2} + y = \frac{2}{2} + 1 = 1 + 1 = 2$

Q. One mole of Mg3​N2​ react with excess of water to form x mole of Ammonia and One mole of LiH react with H2​O to give y mole of H2​ find (2x​+y)=

LiH+H2​O→H2​+LiOH (y) 2x​+y=22​+1=1+1=2

Q. One mole of $M g_{3} N_{2}$ react with excess of water to form $x$ mole of Ammonia and One mole of $L i H$ react with $H_{2} O$ to give $y$ mole of $H_{2}$ find $(\frac{x}{2} + y) =$

$L i H + H_{2} O \to H_{2} + L i O H$
$(y)$
$\frac{x}{2} + y = \frac{2}{2} + 1 = 1 + 1 = 2$