One mole of ideal monoatomic gas (γ = 5/3) is mixed with one mole of diatomic gas (γ = 7/5). What is γ for the mixture? γ Denotes the ratio of specific heat at constant pressure, to that at constant volume.

Question

One mole of ideal monoatomic gas (&gamma; = 5/3) is mixed with one mole of diatomic gas (&gamma; = 7/5). What is &gamma; for the mixture? &gamma; Denotes the ratio of specific heat at constant pressure, to that at constant volume. (A) 3/2 (B) 23/15 (C) 35/23 (D) 4/3

Tardigrade Admin · Accepted Answer

Q = Q1 + Q2 (n1+n2/&gamma;m-1) = (n1/&gamma;1-1)+(n2/&gamma; 2-1) &gamma;m = (3/2)

Q. One mole of ideal monoatomic gas $(γ = 5/3)$ is mixed with one mole of diatomic gas $(γ = 7/5)$ . What is $γ$ for the mixture? $γ$ Denotes the ratio of specific heat at constant pressure, to that at constant volume.

3/2

23/15

35/23

4/3

$Q = Q_{1} + Q_{2}$
$\frac{n _{1} + n _{2}}{γ _{m} - 1} = \frac{n _{1}}{γ _{1} - 1} + \frac{n _{2}}{γ _{2} - 1}$
$γ_{m} = \frac{3}{2}$

Q. One mole of ideal monoatomic gas (γ=5/3) is mixed with one mole of diatomic gas (γ=7/5). What is γ for the mixture? γ Denotes the ratio of specific heat at constant pressure, to that at constant volume.

3/2

23/15

35/23

4/3

Q=Q1​+Q2​ γm​−1n1​+n2​​=γ1​−1n1​​+γ2​−1n2​​ γm​=23​

Q. One mole of ideal monoatomic gas $(γ = 5/3)$ is mixed with one mole of diatomic gas $(γ = 7/5)$ . What is $γ$ for the mixture? $γ$ Denotes the ratio of specific heat at constant pressure, to that at constant volume.

$Q = Q_{1} + Q_{2}$
$\frac{n _{1} + n _{2}}{γ _{m} - 1} = \frac{n _{1}}{γ _{1} - 1} + \frac{n _{2}}{γ _{2} - 1}$
$γ_{m} = \frac{3}{2}$