One mole of ethyl acetate on treatment with an excess of LiAlH4 in dry ether and subsequent acidification produces

Question

One mole of ethyl acetate on treatment with an excess of LiAlH4 in dry ether and subsequent acidification produces (A) 1 mol acetic acid + 1 mol ethyl alcohol (B) 1 mol ethyl alcohol + 1 mol methyl alcohol (C) 2 moles of ethyl alcohol (D) 1 mol of 2-butanol

Tardigrade Admin · Accepted Answer

underset textEthyl acetateCH 3 COOC 2 H 5 xrightarrow[ textdry ether] LiAlH 4 / H 3 O + longrightarrow CH 3 CH 2 OH + C 2 H 5 OH

Q. One mole of ethyl acetate on treatment with an excess of $L i A l H_{4}$ in dry ether and subsequent acidification produces

$1$ mol acetic acid $+ 1$ mol ethyl alcohol

$1$ mol ethyl alcohol $+ 1$ mol methyl alcohol

$2$ moles of ethyl alcohol

$1$ mol of $2$ -butanol

$Ethyl acetate C H_{3} COO C_{2} H_{5} L i A l H_{4} / H_{3} O^{+} dry ether ⟶ C H_{3} C H_{2} O H + C_{2} H_{5} O H$

Q. One mole of ethyl acetate on treatment with an excess of LiAlH4​ in dry ether and subsequent acidification produces

1 mol acetic acid +1 mol ethyl alcohol

1 mol ethyl alcohol +1 mol methyl alcohol

2 moles of ethyl alcohol

1 mol of 2-butanol