One mole of an ideal gas undergoes a cyclic process ABCDA as shown in the P-V diagram, Tire net work done in the process is (1 atm = 106 dyne cm-2 )

Question

One mole of an ideal gas undergoes a cyclic process ABCDA as shown in the P-V diagram, Tire net work done in the process is (1 atm = 106 dyne cm-2 ) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/35b908734d233cba25e0cfaf788cc7c4-.png" /> (A)  500 J  (B)  700 J  (C)  800 J  (D)  900 J

Tardigrade Admin · Accepted Answer

From the P-V diagram, Work done, W = area under the P - V diagram beginaligned W &= AB × BC W &=2 text litre × 4 atm W &=2 × 10-3 × 4 × 1.03 × 105 W &=8 × 100 W &=800 J endaligned

Q. One mole of an ideal gas undergoes a cyclic process $A BC D A$ as shown in the $P - V$ diagram, Tire net work done in the process is
$(1 a t m = 1 0^{6}$ dyne $c m^{- 2}$ )

$500 J$

$700 J$

$800 J$

$900 J$

From the P-V diagram,
Work done, $W =$ area under the $P - V$ diagram
$< b r / > < b r / > W < b r / > W < b r / > W < b r / > W < b r / > W = A B \times BC = 2 litre \times 4 a t m = 2 \times 1 0^{- 3} \times 4 \times 1.03 \times 1 0^{5} = 8 \times 100 = 800 J < b r / > < b r / >$

Q. One mole of an ideal gas undergoes a cyclic process ABCDA as shown in the P−V diagram, Tire net work done in the process is (1atm=106 dyne cm−2 )

500J

700J

800J

900J