One mole of an ideal gas at an initial temperature of TK does 6R joules of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is 5/3 , the final temperature of gas will be

Question

One mole of an ideal gas at an initial temperature of TK does 6R joules of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is 5/3 , the final temperature of gas will be (A) (.T+2.4.)K (B) (.T-2.4.)K (C) (.T+4.)K (D) (.T-4.)K

Tardigrade Admin · Accepted Answer

W=(R (Ti - Tf)/&gamma; - 1)⇒ 6R=(R (T - Tf)/((5)3 - 1))⇒ Tf=(.T-4.)K

Q. One mole of an ideal gas at an initial temperature of $T K$ does $6 R$ joules of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is $5/3,$ the final temperature of gas will be

$(T + 2.4) K$

$(T - 2.4) K$

$(T + 4) K$

$(T - 4) K$

$W = \frac{R ( T _{i} - T _{f} )}{γ - 1} \Rightarrow 6 R = \frac{R ( T - T _{f} )}{( \frac{5}{3} - 1 )} \Rightarrow T_{f} = (T - 4) K$

Q. One mole of an ideal gas at an initial temperature of TK does 6R joules of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is 5/3, the final temperature of gas will be

(T+2.4)K

(T−2.4)K

(T+4)K

(T−4)K