One mole of an ideal gas at a temperature T1 K expands slowly according to the law (p/V)= constant. Its final temperature is T2 K . The work done by the gas is

Question

One mole of an ideal gas at a temperature T1 K expands slowly according to the law (p/V)= constant. Its final temperature is T2 K . The work done by the gas is (A) R(T2-T1) (B) 2 R(T2-T1) (C) (R/2)(T2-T1) (D) (2 R/3)(T2-T1)

Tardigrade Admin · Accepted Answer

P V-1=C Comparing P VN=C N=-1 W=(n R(T1-T2)/N-1)= (1 × R(T1-T2)/-2) W=(R(T2-T1)/2)

Q. One mole of an ideal gas at a temperature $T_{1} K$ expands slowly according to the law $\frac{p}{V} =$ constant. Its final temperature is $T_{2} K .$ The work done by the gas is

$R (T_{2} - T_{1})$

$2 R (T_{2} - T_{1})$

$\frac{R}{2} (T_{2} - T_{1})$

$\frac{2 R}{3} (T_{2} - T_{1})$

$P V^{- 1} = C$
Comparing $P V^{N} = C$
$N = - 1$
$W = \frac{n R ( T _{1} - T _{2} )}{N - 1} =$
$\frac{1 \times R ( T _{1} - T _{2} )}{- 2}$
$W = \frac{R ( T _{2} - T _{1} )}{2}$

Q. One mole of an ideal gas at a temperature T1​K expands slowly according to the law Vp​= constant. Its final temperature is T2​K. The work done by the gas is

R(T2​−T1​)

2R(T2​−T1​)

2R​(T2​−T1​)

32R​(T2​−T1​)