One mole of an ideal gas at 27° C is taken from A to B as shown in the given P V indicator diagram. The work done by the system will be × 10-1 J [Given: R=8.3 J / mol e K, ln 2=0.6931 ]

Question

One mole of an ideal gas at 27° C is taken from A to B as shown in the given P V indicator diagram. The work done by the system will be × 10-1 J [Given: R=8.3 J / mol e K, ln 2=0.6931 ] (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Process of isothermal W=n R T l n((V2/V1)) =1 × 8.3 × 300 × ln 2 =17258 × 10-1 J

Q. One mole of an ideal gas at $2 7^{\circ} C$ is taken from $A$ to $B$ as shown in the given $P V$ indicator diagram. The work done by the system will be_______ $\times 1 0^{- 1} J$ [Given: $R = 8.3 J /$ mol $eK, ln 2 = 0.6931$ ]

Process of isothermal
$W = n RTl n (\frac{V _{2}}{V _{1}})$
$= 1 \times 8.3 \times 300 \times ln 2$
$= 17258 \times 1 0^{- 1} J$

Q. One mole of an ideal gas at 27∘C is taken from A to B as shown in the given PV indicator diagram. The work done by the system will be_______ ×10−1J [Given: R=8.3J/ mol eK,ln2=0.6931 ]

Process of isothermal W=nRTln(V1​V2​​) =1×8.3×300×ln2 =17258×10−1J

Q. One mole of an ideal gas at $2 7^{\circ} C$ is taken from $A$ to $B$ as shown in the given $P V$ indicator diagram. The work done by the system will be_______ $\times 1 0^{- 1} J$ [Given: $R = 8.3 J /$ mol $eK, ln 2 = 0.6931$ ]

Process of isothermal
$W = n RTl n (\frac{V _{2}}{V _{1}})$
$= 1 \times 8.3 \times 300 \times ln 2$
$= 17258 \times 1 0^{- 1} J$