(Symm.alkene)RCH=CHR(i)O3(ii)Zn,H2O2RCHO
Molecular mass of RCHO=44 ⇒R+12+1+16=44
Mol. mass of R=44−29=15
This is possible, only when R is −CH3 group.
The aldehyde is CH3CHO and the symmetrical alkene is CH3CH=CHCH3 2-ButeneCH3CH=CHCH3(i)O3(ii)Zn,H2OAcetaldehyde2CH3CHO