One mole of a non-volatile solute is dissolved in two moles of water. The vapor pressure of the solution relative to that of water is

Question

One mole of a non-volatile solute is dissolved in two moles of water. The vapor pressure of the solution relative to that of water is (A) 2/3 (B) 1/3 (C) 1/2 (D) 3/2

Tardigrade Admin · Accepted Answer

(p°-O text soln /p)=(1/1+2)=(1/3) (mole fraction of solute in solution) or 1-(O text soln /p)=(1/3) or (O text soln /p)=1-(1/3)=(2/3)

Q. One mole of a non-volatile solute is dissolved in two moles of water. The vapor pressure of the solution relative to that of water is

2/3

1/3

1/2

3/2

$\frac{p ^{\circ} - O _{soln}}{p} = \frac{1}{1 + 2} = \frac{1}{3}$

(mole fraction of solute in solution)

or $1 - \frac{O _{soln}}{p} = \frac{1}{3}$

or $\frac{O _{soln}}{p} = 1 - \frac{1}{3} = \frac{2}{3}$

Q. One mole of a non-volatile solute is dissolved in two moles of water. The vapor pressure of the solution relative to that of water is

2/3

1/3

1/2

3/2

pp∘−Osoln ​​=1+21​=31​ (mole fraction of solute in solution) or 1−pOsoln ​​=31​ or pOsoln ​​=1−31​=32​

$\frac{p ^{\circ} - O _{soln}}{p} = \frac{1}{1 + 2} = \frac{1}{3}$

(mole fraction of solute in solution)

or $1 - \frac{O _{soln}}{p} = \frac{1}{3}$

or $\frac{O _{soln}}{p} = 1 - \frac{1}{3} = \frac{2}{3}$