One mole of a monoatomic real gas satisfies the equation p(V - b)=RT where b is a constant. The relationship of interatomic potential V(.r.) and interatomic distance r for the gas is given by

Question

One mole of a monoatomic real gas satisfies the equation p(V - b)=RT where b is a constant. The relationship of interatomic potential V(.r.) and interatomic distance r for the gas is given by (A) Option 1

(B)

(C)

(D)

Tardigrade Admin · Accepted Answer

Here the given equation is P(.V-b.)=RT . On comparing with van der Waals' equation [P + (a/V2)][.V-b].=RT That is a=0 . It means only repulsive forces are present which are contributive only at very close distance so the potential energy will increase abruptly. i.e., graph C is correct.

Q. One mole of a monoatomic real gas satisfies the equation p(V−b)=RT where b is a constant. The relationship of interatomic potential V(r) and interatomic distance r for the gas is given by

Here the given equation is P(V−b)=RT . On comparing with van der Waals' equation [P+V2a​][V−b]=RT That is a=0 . It means only repulsive forces are present which are contributive only at very close distance so the potential energy will increase abruptly. i.e., graph C is correct.

Q. One mole of a monoatomic real gas satisfies the equation $p (V - b) = RT$ where b is a constant. The relationship of interatomic potential $V (r)$ and interatomic distance r for the gas is given by