One mole of a gas at NTP is suddenly allowed to expand to three times its volume. If Cv= 2R, then the final pressure of the gas will be nearest to

Question

One mole of a gas at NTP is suddenly allowed to expand to three times its volume. If Cv= 2R, then the final pressure of the gas will be nearest to (A) 0.1 atm (B) 0.2 atm (C) 0.4 atm (D) 0.6 atm

Tardigrade Admin · Accepted Answer

p1V1&gamma;=p2V2 &gamma;.Here Cp=3 R and &gamma;=Cp/Cv=(3/2)

Q. One mole of a gas at NTP is suddenly allowed to expand to three times its volume. If $C_{v}$ = 2R, then the final pressure of the gas will be nearest to

0.1 atm

0.2 atm

0.4 atm

0.6 atm

$p_{1} V_{1} γ = p_{2} V_{2} γ . Here C_{p} = 3 R an d γ = C_{p} / C_{v} = \frac{3}{2}$

Q. One mole of a gas at NTP is suddenly allowed to expand to three times its volume. If Cv​= 2R, then the final pressure of the gas will be nearest to