One litre hard water contains 12.00 mg Mg 2+. Milliequivalents of washing soda required to remove its hardness is

Question

One litre hard water contains 12.00 mg Mg 2+. Milliequivalents of washing soda required to remove its hardness is (A) 1 (B) 12.16 (C) 1 × 10-3 (D) 12.16 × 10-3

Tardigrade Admin · Accepted Answer

underset1 g wqMg2++ underset1 g eq.Na2CO3 → MgCO3+2Na+ 12 g or 12000 mg of Mg 2+=1000 millieq ∴ 12 mg Mg 2+=1 millieq. Na 2 CO 3

Q. One litre hard water contains $12.00 m g M g^{2 +}$ . Milliequivalents of washing soda required to remove its hardness is

$1$

$12.16$

$1 \times 1 0^{- 3}$

$12.16 \times 1 0^{- 3}$

$1 g wq M g^{2 +} + 1 g e q . N a_{2} C O_{3} \to M g C O_{3} + 2 N a^{+}$

$12 g$ or $12000 m g$ of $M g^{2 +} = 1000$ millieq

$∴ 12 m g M g^{2 +} = 1$ millieq. $N a_{2} C O_{3}$

Q. One litre hard water contains 12.00mgMg2+. Milliequivalents of washing soda required to remove its hardness is

1

12.16

1×10−3

12.16×10−3

1gwqMg2+​+1geq.Na2​CO3​​→MgCO3​+2Na+ 12g or 12000mg of Mg2+=1000 millieq ∴12mgMg2+=1 millieq. Na2​CO3​

Q. One litre hard water contains $12.00 m g M g^{2 +}$ . Milliequivalents of washing soda required to remove its hardness is

$1$

$12.16$

$1 \times 1 0^{- 3}$

$12.16 \times 1 0^{- 3}$

$1 g wq M g^{2 +} + 1 g e q . N a_{2} C O_{3} \to M g C O_{3} + 2 N a^{+}$

$12 g$ or $12000 m g$ of $M g^{2 +} = 1000$ millieq

$∴ 12 m g M g^{2 +} = 1$ millieq. $N a_{2} C O_{3}$