Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. One litre hard water contains $12.00\, mg\, Mg ^{2+}$. Milliequivalents of washing soda required to remove its hardness is

Some Basic Concepts of Chemistry

Solution:

$\underset{1\,g\,wq}{Mg^{2+}}+\underset{1\,g\,eq.}{Na_{2}CO_{3}} \to MgCO_{3}+2Na^{+}$

$12\, g$ or $12000 \,mg$ of $Mg ^{2+}=1000$ millieq

$\therefore 12 \,mg \,Mg ^{2+}=1$ millieq. $Na _{2} CO _{3}$