One isotope of a non-metallic element has mass number 127 and 74 neutrons in the nucleus. The anion derived from the isotope has 54 electrons. Hence, symbol for the anion is

Question

One isotope of a non-metallic element has mass number 127 and 74 neutrons in the nucleus. The anion derived from the isotope has 54 electrons. Hence, symbol for the anion is (A)  54127 X- (B)  53127 X- (C)  5374 X- (D)  5474 X-

Tardigrade Admin · Accepted Answer

Z A X = A - N A X= 127-74127 X = 53127 X There are 54 electrons. Hence, ionic species is 53127 X -

Q. One isotope of a non-metallic element has mass number $127$ and $74$ neutrons in the nucleus. The anion derived from the isotope has $54$ electrons. Hence, symbol for the anion is

$_{54}^{127} X^{-}$

$_{53}^{127} X^{-}$

$_{53}^{74} X^{-}$

$_{54}^{74} X^{-}$

$_{Z}^{A} X =_{A - N}^{A} X =_{127 - 74}^{127} X =_{53}^{127} X$
There are $54$ electrons. Hence, ionic species is $_{53}^{127} X^{-}$

Q. One isotope of a non-metallic element has mass number 127 and 74 neutrons in the nucleus. The anion derived from the isotope has 54 electrons. Hence, symbol for the anion is

54127​X−

53127​X−

5374​X−

5474​X−