One gas bleaches the colour of flowers by reduction and another gas by oxidation. The gases respectively are

Question

One gas bleaches the colour of flowers by reduction and another gas by oxidation. The gases respectively are (A) NH3 and SO3 (B) H2S and Br2 (C) SO2 and Cl2 (D) CO and Cl2

Tardigrade Admin · Accepted Answer

SO2 in presence of moisture acts as a bleaching agent. This is due to the reducing nature of SO2. SO2+2H2O → H2SO4+2H Coloured matter +H → colourless matter Chlorine reacts with water forming HCl and HClO (hypochlorous acid). HClO is not so stable and decomposes giving nascent oxygen. Which is responsible for oxidising and bleaching properties of chlorine Cl2+H2O → HCl +HClO HClO → HCl+O coloured matter + nascent oxygen → colourless matter

Q. One gas bleaches the colour of flowers by reduction and another gas by oxidation. The gases respectively are

$N H_{3}$ and $S O_{3}$

$H_{2} S$ and $B r_{2}$

$S O_{2}$ and $C l_{2}$

$CO$ and $C l_{2}$

Q. One gas bleaches the colour of flowers by reduction and another gas by oxidation. The gases respectively are

NH3​ and SO3​

H2​S and Br2​

SO2​ and Cl2​

CO and Cl2​

$N H_{3}$ and $S O_{3}$

$H_{2} S$ and $B r_{2}$

$S O_{2}$ and $C l_{2}$

$CO$ and $C l_{2}$