Question

One-fourth length of a spring of force constant $k$ is cut away. The force constant of the remaining spring will be

• A. $\frac{3}{4}k$
• B. $\frac{4}{3}k$
• C. k
• D. 4k

Answer 1

Answer: (B)

$BYusingk\propto \frac{1}{l}$
Since, one-fourth length is cut away so remaining length is
$\frac{3}{4}th$hence k becomes $\frac{4}{3}\times i.e,k^{\prime }=\frac{4}{3}k$