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  4. One-fourth length of a spring of force constant k is cut away. The force constant of the remaining spring will be

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Q. One-fourth length of a spring of force constant $k$ is cut away. The force constant of the remaining spring will be

AFMCAFMC 2010Oscillations

Solution:

$BY \, using \, k \propto \frac{1}{l}$
Since, one-fourth length is cut away so remaining length is
$\frac{3}{4}th$hence k becomes $\frac{4}{3} \times \, i.e, k'=\frac{4}{3}k$