One electric cell (having emf of 2 V internal resistance of 0.1 Ω ) and other electric cell (having emf of 4 V internal resistance of 0.2 Ω ) are connected in parallel to each other. Then its equivalent emf will be . V

Question

One electric cell (having emf of 2 V internal resistance of 0.1 Ω ) and other electric cell (having emf of 4 V internal resistance of 0.2 Ω ) are connected in parallel to each other. Then its equivalent emf will be . V (A) 2.57 (B) 2.67 (C) 1.33 (D) 0.38

Tardigrade Admin · Accepted Answer

E text net =((E1/r1)+(E2/r2)/(1)r1+(1)r2

Q. One electric cell (having emf of $2 V &$ internal resistance of $0.1 Ω$ ) and other electric cell (having emf of $4 V &$ internal resistance of $0.2 Ω$ ) are connected in parallel to each other. Then its equivalent emf will be . ______ $V$

2.57

2.67

1.33

0.38

$E_{net} = \frac{\frac{E _{1}}{r _{1}} + \frac{E _{2}}{r _{2}}}{\frac{1}{r _{1}} + \frac{1}{r _{2}}}$

Q. One electric cell (having emf of 2V& internal resistance of 0.1Ω ) and other electric cell (having emf of 4V& internal resistance of 0.2Ω ) are connected in parallel to each other. Then its equivalent emf will be . ______V