One circular ring and one circular disc, both are having the same mass and radius. Then both of their moments of inertia about the axes passing through their centres and perpendicular to their planes, will be in the ratio

Question

One circular ring and one circular disc, both are having the same mass and radius. Then both of their moments of inertia about the axes passing through their centres and perpendicular to their planes, will be in the ratio (A) 1: 1 (B) 2: 1 (C) 1: 2 (D) 4: 1

Tardigrade Admin · Accepted Answer

The ratio of moments of inertia (Iring/Idisc)=(MR2/1/2MR2)=2:1

Q. One circular ring and one circular disc, both are having the same mass and radius. Then both of their moments of inertia about the axes passing through their centres and perpendicular to their planes, will be in the ratio

1 : 1

2 : 1

1 : 2

4 : 1

The ratio of moments of inertia
$\frac{I _{r in g}}{I _{d i sc}} = \frac{M R ^{2}}{1/2 M R ^{2}} = 2 : 1$

Q. One circular ring and one circular disc, both are having the same mass and radius. Then both of their moments of inertia about the axes passing through their centres and perpendicular to their planes, will be in the ratio

1 : 1

2 : 1

1 : 2

4 : 1

The ratio of moments of inertia Idisc​Iring​​=1/2MR2MR2​=2:1

The ratio of moments of inertia
$\frac{I _{r in g}}{I _{d i sc}} = \frac{M R ^{2}}{1/2 M R ^{2}} = 2 : 1$