One centimetre on the main scale of a vernier callipers is divided into 10 equal parts. If 10 divisions of vernier coincide with 8 small divisions of the main scale, the least count of vernier callipers is

Question

One centimetre on the main scale of a vernier callipers is divided into 10 equal parts. If 10 divisions of vernier coincide with 8 small divisions of the main scale, the least count of vernier callipers is (A) 0.01 cm (B) 0.02 cm (C) 0.05 cm (D) 0.005 cm

Tardigrade Admin · Accepted Answer

The value of 1 division of main scale =(1/10)= 0.1 cm The value of 1 division of vernier scale =(8 × 0.1/10)=0.08 cm Thus L.C. =0.1-0.08=0.02 cm

Q. One centimetre on the main scale of a vernier callipers is divided into $10$ equal parts. If $10$ divisions of vernier coincide with $8$ small divisions of the main scale, the least count of vernier callipers is

$0.01 c m$

$0.02 c m$

$0.05 c m$

$0.005 c m$

The value of $1$ division of main scale $= \frac{1}{10} = 0.1 c m$
The value of $1$ division of vernier scale $= \frac{8 \times 0.1}{10} = 0.08 c m$
Thus L.C. $= 0.1 - 0.08 = 0.02 c m$

Q. One centimetre on the main scale of a vernier callipers is divided into 10 equal parts. If 10 divisions of vernier coincide with 8 small divisions of the main scale, the least count of vernier callipers is

0.01cm

0.02cm

0.05cm

0.005cm