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  4. One centimetre on the main scale of a vernier callipers is divided into 10 equal parts. If 10 divisions of vernier coincide with 8 small divisions of the main scale, the least count of vernier callipers is

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Q. One centimetre on the main scale of a vernier callipers is divided into $10$ equal parts. If $10$ divisions of vernier coincide with $8$ small divisions of the main scale, the least count of vernier callipers is

Physical World, Units and Measurements

Solution:

The value of $1$ division of main scale $=\frac{1}{10}= 0.1 \,cm $
The value of $1$ division of vernier scale $=\frac{8 \times 0.1}{10}=0.08 cm$
Thus L.C. $=0.1-0.08=0.02\, cm$