On treatment of 100 mL of 0.1 M solution of CoCl 3 ⋅ 6 H 2 O with excess AgNO 3 ; 1.2 × 1022 ions are precipitated. The complex is

Question

On treatment of 100 mL of 0.1 M solution of CoCl 3 ⋅ 6 H 2 O with excess AgNO 3 ; 1.2 × 1022 ions are precipitated. The complex is (A) [ Co ( H 2 O )6] Cl 3 (B) [ Co ( H 2 O )5 Cl ] Cl 2 ⋅ H 2 O (C) [ Co ( H 2 O )4 Cl 2] Cl ⋅ 2 H 2 O (D) [ Co ( H 2 O )3 Cl 3] ⋅ 3 H 2 O

Tardigrade Admin · Accepted Answer

Millimoles of AgNO 3=(1.2 × 1022/6 × 1023) × 1000=20 Millimoles of CoCl 3 ⋅ 6 H 2 O =0.1 × 100=10 ∴ Each mole of CoCl 3 ⋅ 6 H 2 O gives two chloride ions. ∴ [ Co ( H 2 O )5 Cl ] Cl 2 ⋅ H 2 O

Q. On treatment of $100 m L$ of $0.1 M$ solution of $C o C l_{3} \cdot 6 H_{2} O$ with excess $A g N O_{3}; 1.2 \times 1 0^{22}$ ions are precipitated. The complex is

$[C o (H_{2} O)_{6}] C l_{3}$

$[C o (H_{2} O)_{5} Cl] C l_{2} \cdot H_{2} O$

$[C o (H_{2} O)_{4} C l_{2}] Cl \cdot 2 H_{2} O$

$[C o (H_{2} O)_{3} C l_{3}] \cdot 3 H_{2} O$

Millimoles of $A g N O_{3} = \frac{1.2 \times 1 0 ^{22}}{6 \times 1 0 ^{23}} \times 1000 = 20$

Millimoles of $C o C l_{3} \cdot 6 H_{2} O = 0.1 \times 100 = 10$

$∴$ Each mole of $C o C l_{3} \cdot 6 H_{2} O$ gives two chloride ions.

$∴ [C o (H_{2} O)_{5} Cl] C l_{2} \cdot H_{2} O$

Q. On treatment of 100mL of 0.1M solution of CoCl3​⋅6H2​O with excess AgNO3​;1.2×1022 ions are precipitated. The complex is

[Co(H2​O)6​]Cl3​

[Co(H2​O)5​Cl]Cl2​⋅H2​O

[Co(H2​O)4​Cl2​]Cl⋅2H2​O

[Co(H2​O)3​Cl3​]⋅3H2​O